We represent the graph with a map. Keys are the nodes of the graph, values are another map mapping each child to its distance to its parent.

Thus, the representation for this graph:

is:

{:A {:B 85, :C 217 }, :B { :C 25 }, :C {} }

Symbols (:A, :B etc.) are used to represent the nodes, but any type would be fine.

We don't want our algorithms to rely on a particular graph structure so access to the graph is made via helper functions. The distance function return the distance between two nodes and the children function return a sequence containing the children for a given node.

(defn distance [net nodesrc nodedst] ((net nodesrc) nodedst)) (defn children [net node] (keys (net node)))

In the Dijkstra's algorithm, nodes' distances to the initial node are progressively updated and the predecessor of a node, for its known shortest distance, is updated. We take the same approach but we don't store distances with a value of infinity, i.e. the distances to the initial node for nodes not yet explored are not kept. We call "root" the initial node in our code, and "rdistance" the distance to the root for a given node.

The rdistances are stored in a sorted map, rdists. Each rdistance is mapped to another map mapping each node to their predecessor for this rdistance. This allow to efficiently implement the

u := vertex in Q with smallest dist[]operation describe in the pseudo-code: we just need to take the first element of the map. Once the smallest rdistance is found, we removed it from the map to save space. How do we keep the rdistance of a node if rdistances are removed from the rdists map? Predecessors and rdistances are kept together in the preds map. Rdists is only used for newly discovered rdistances. Note that with this scheme we don't need a Q set like in the pseudo-code, rdists acting like a one. When rdists is empty, that mean we have explored all reachable nodes.

When the node with the smallest rdistance has been found, we need to update the rdistances of its children. This is done in the update-rdists function.

(defn- update-rdists [rdists preds net node dist children distance] "return [rdists preds] updated" (reduce (fn [acc x] (let [curdist (+ dist (distance net node x)) prevdist (second (preds x)) nrdists (first acc) npreds (second acc)] (if (nil? prevdist) [(add-rdist nrdists x node curdist) (assoc npreds x [node curdist])] (if (< curdist prevdist) [(add-rdist nrdists x node curdist prevdist) (assoc npreds x [node curdist])] [nrdists npreds])))) [rdists preds] (children net node)))When true, the condition

Uncommenting the printf function in the code allows us to follow the steps of the algorithm.

minnode = :A preds = {:E [:A 173], :C [:A 217], :B [:A 85], :A [:A 0]} rdists ={85 {:B :A}, 173 {:E :A}, 217 {:C :A}}For instance, the previous line means that the node with the smallest rdistance was A, then its children' rdistances were updated. The rdistance from :B is 85 and its predecessor is A, the one from :E is 173 etc. In this case rdists and preds convey nearly the same information, this is because its one of the first iteration of the algorithm. Things change after when the exploration progress.

Please feel free to criticize and improve the algorithm. One idea could be to use the memoize function to cach the result of the dijkstra function.

**If you know a good test suite for graph algorithms, please post a comment.**

**Full code is available here **